JEE MAIN - Physics (2023 - 15th April Morning Shift - No. 21)
In the given figure the total charge stored in the combination of capacitors is $100~ \mu \mathrm{C}$. The value of ' $x$ ' is _________.
_15th_April_Morning_Shift_en_21_1.png)
Responder
5
Explicação
Charge on $\mathrm{C}_1$ is $\mathrm{Q}_1=2 \times 10=20 \mu \mathrm{C}$ .....(i)
Charge on $\mathrm{C}_2$ is $\mathrm{Q}_2=\mathrm{x} \times 10=10 \mathrm{x} \mu \mathrm{C}$ .....(ii)
Charge on $\mathrm{C}_3$ is $\mathrm{Q}_3=3 \times 10=30 \mu \mathrm{C}$ .....(iii)
Total charge $20+10 \mathrm{x}+30=100$ $\Rightarrow x=5$
Charge on $\mathrm{C}_2$ is $\mathrm{Q}_2=\mathrm{x} \times 10=10 \mathrm{x} \mu \mathrm{C}$ .....(ii)
Charge on $\mathrm{C}_3$ is $\mathrm{Q}_3=3 \times 10=30 \mu \mathrm{C}$ .....(iii)
Total charge $20+10 \mathrm{x}+30=100$ $\Rightarrow x=5$